Nope - but it IS divisible by 3.
6 is not divisible by 162. 162 is divisible by 6.
3 [lots] of 200 = 6003 [lots] of 200 = 6003 [lots] of 200 = 6003 [lots] of 200 = 600
If it is divisible by 2 and 3, it is divisible by 6.
if a number is divisible by 2 and 3 then its divisible by 6
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
Answer:6003 is not a prime number. It is a composite number.Definition:A prime number has exactly two factors: 1 (also known as unity) and itself. A composite number has more than two factors; in other words, it has at least one factor besides 1 and itself.Explanation:Any number for which the digits add to a number divisible by 3 is also divisible by 3, so it also has 3 as a factor. The sum of the digits of 6003 is 6 + 0 + 0 + 3 = 9, which is divisible by 3, which means 6003 is divisible by 3. Therefore, 6003 is a composite number.
1, 3, 9, 23, 29, 69, 87, 207, 261, 667, 2001, 6003
(vi)iii (vi)iii = 1000*6+3 = 6003
6003 / 100 = 60.033740 / 60.03 = 62.30218224So...3740 is 62.3% of 6003
6 is not divisible by 162. 162 is divisible by 6.
3 [lots] of 200 = 6003 [lots] of 200 = 6003 [lots] of 200 = 6003 [lots] of 200 = 600
If it is divisible by 2 and 3, it is divisible by 6.
If a number is divisible by 2 and 3, it is divisible by 6.
if a number is divisible by 2 and 3 then its divisible by 6
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.