2 x 6 + 0 = 12
2 x 1 + 2 = 4
4 is not [divisible by] 8, so 60 is not divisible by 8.
(The remainder when 60 is divided by 8 is 4).
To test divisibility by 8:
Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit.
If this sum is divisible by 8 so is the original number.
(Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.)
If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
If the last 3 digits are divisible by 8, the number is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
not divisible by any number
Yes because 480/8 = 60
Yes. 60/2 is 30. (If a number ends in 0, 2, 4, 6, or 8 it is divisible by two.)
Yes, not evenly, quotient is 60, remainder is 6
60 000 000.
56.
60/4 = 15 Therefore, 60 is divisible by 4.
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
Unless I've made a mistake, it's 3600 which is 60 * 60.
numbers divisible by 60 are the multiples of 60: 60, 120, 180,240,400, 360, 420,...
120120/8 = 15120/3 = 40120/2 = 60
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.