2 x 6 + 0 = 12
2 x 1 + 2 = 4
4 is not [divisible by] 8, so 60 is not divisible by 8.
(The remainder when 60 is divided by 8 is 4).
To test divisibility by 8:
Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit.
If this sum is divisible by 8 so is the original number.
(Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.)
If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
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A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
If the last 3 digits are divisible by 8, the number is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
not divisible by any number