To check for divisibility by 8 add four times the hundreds digit to twice the tens digit to the units digit; if this sum is divisible by 8 then so is the original number:
For 728: 4×7 + 2×2 + 8 = 40 which is divisible by 8, so 728 is divisible by 8.
The test can be repeated on the sum, so if the test is repeatedly applied to the sums until a single digit remains, only if this single digit is 8 then the original number is divisible by 8 (otherwise the excess of this number over a multiple of 8 is the remainder when the original number is divided by 8, ie if it is less than 8 it is the remainder, else it is 9 and the remainder is 9 - 8 = 1).
For 728: 4×7 + 2×2 + 8= 40
40: 4×0 + 2×4 + 0 = 8
This single digit is 8, so 728 is divisible by 8.
Oh, dude, let me put on my math hat for a sec. So, if we're trying to figure out what times 8 equals 728, we just divide 728 by 8. That gives us 91. So, technically, 8 times 91 equals 728. Math, man, it's wild.
If the last 3 digits are divisible by 8, the number is divisible by 8.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
152 is divisible by 8, and the answer is 19.
If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!
No.
Any of its factors - 1,2,4,7,8,13,14,26,28,52,56,91,104,182,364,728
To find out how many times 8 can go into 728, you divide 728 by 8. Performing the division, ( 728 ÷ 8 = 91 ). Therefore, 8 can go into 728 a total of 91 times.
28 is divisible by 4 so divide by 4 728 = 4 * x 728 = 4x 728/4 = 182 x = 182
Oh, dude, let me put on my math hat for a sec. So, if we're trying to figure out what times 8 equals 728, we just divide 728 by 8. That gives us 91. So, technically, 8 times 91 equals 728. Math, man, it's wild.
.728 = 728/1000 (the last digit is in the Thousands place so it is the whole number over one thousand) They are both divisible by 2 so: 728 / 2 = 364 and 1000 / 2 = 500 728/1000 = 364/500 That is also divisible by 2 so: 364 / 2 = 182 and 500 / 2 = 250 That is also divisible by 2 so: 182 / 2 = 91 and 250 / 2 = 125 728/1000 = 364/500 = 182/250 = 91/125 91/125 is fully simplified and is your answer.
All of these numbers go into 728 evenly: 1, 2, 4, 7, 8, 13, 14, 26, 28, 52, 56, 91, 104, 182, 364, 728.
The LCM is 728.
60 minutes = 1 hour 728 minutes = 12 hours 8 minutes
If the last 3 digits are divisible by 8, the number is divisible by 8.
The factors of 728 are: 1, 2, 4, 7, 8, 13, 14, 26, 52, 56, 91, 104, 182, 364, and 728.The prime factors of 728 are: 2, 7, and 13.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.