To determine if 728 is divisible by 8, we need to check if 8 is a factor of 728. To do this, we divide 728 by 8. If the division results in a whole number without any remainder, then 728 is divisible by 8. In this case, 728 ÷ 8 = 91, so yes, 728 is divisible by 8.
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To check for divisibility by 8 add four times the hundreds digit to twice the tens digit to the units digit; if this sum is divisible by 8 then so is the original number:
For 728: 4×7 + 2×2 + 8 = 40 which is divisible by 8, so 728 is divisible by 8.
The test can be repeated on the sum, so if the test is repeatedly applied to the sums until a single digit remains, only if this single digit is 8 then the original number is divisible by 8 (otherwise the excess of this number over a multiple of 8 is the remainder when the original number is divided by 8, ie if it is less than 8 it is the remainder, else it is 9 and the remainder is 9 - 8 = 1).
For 728: 4×7 + 2×2 + 8= 40
40: 4×0 + 2×4 + 0 = 8
This single digit is 8, so 728 is divisible by 8.
Oh, dude, let me put on my math hat for a sec. So, if we're trying to figure out what times 8 equals 728, we just divide 728 by 8. That gives us 91. So, technically, 8 times 91 equals 728. Math, man, it's wild.
If the last 3 digits are divisible by 8, the number is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!