To check for divisibility by 8 add four times the hundreds digit to twice the tens digit to the units digit; if this sum is divisible by 8 then so is the original number:
For 728: 4×7 + 2×2 + 8 = 40 which is divisible by 8, so 728 is divisible by 8.
The test can be repeated on the sum, so if the test is repeatedly applied to the sums until a single digit remains, only if this single digit is 8 then the original number is divisible by 8 (otherwise the excess of this number over a multiple of 8 is the remainder when the original number is divided by 8, ie if it is less than 8 it is the remainder, else it is 9 and the remainder is 9 - 8 = 1).
For 728: 4×7 + 2×2 + 8= 40
40: 4×0 + 2×4 + 0 = 8
This single digit is 8, so 728 is divisible by 8.
To find the value of x in the equation x * 8 = 728, you would need to divide 728 by 8. This would give you x = 91. Therefore, 91 times 8 equals 728.
If the last 3 digits are divisible by 8, the number is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!
No.
Any of its factors - 1,2,4,7,8,13,14,26,28,52,56,91,104,182,364,728
28 is divisible by 4 so divide by 4 728 = 4 * x 728 = 4x 728/4 = 182 x = 182
To find the value of x in the equation x * 8 = 728, you would need to divide 728 by 8. This would give you x = 91. Therefore, 91 times 8 equals 728.
.728 = 728/1000 (the last digit is in the Thousands place so it is the whole number over one thousand) They are both divisible by 2 so: 728 / 2 = 364 and 1000 / 2 = 500 728/1000 = 364/500 That is also divisible by 2 so: 364 / 2 = 182 and 500 / 2 = 250 That is also divisible by 2 so: 182 / 2 = 91 and 250 / 2 = 125 728/1000 = 364/500 = 182/250 = 91/125 91/125 is fully simplified and is your answer.
All of these numbers go into 728 evenly: 1, 2, 4, 7, 8, 13, 14, 26, 28, 52, 56, 91, 104, 182, 364, 728.
The LCM is 728.
60 minutes = 1 hour 728 minutes = 12 hours 8 minutes
The factors of 728 are: 1, 2, 4, 7, 8, 13, 14, 26, 52, 56, 91, 104, 182, 364, and 728.The prime factors of 728 are: 2, 7, and 13.
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
These pairs of numbers, when multiplied, equal 728: (1, 728) (2, 364) (4, 182) (7, 104) (8, 91) (13, 56) (14, 52) (26, 28)