Well, isn't that a happy little question? Let's take a closer look. If a number is divisible by 5, it must end in 0 or 5. And if a number is divisible by 9, the sum of its digits must also be divisible by 9. When we add the digits of 90 (which is 9 + 0 = 9), we see that it is divisible by 9 but not by 5.
90 is.LCM(5, 6, 9) = 90.
90 is the LCM
90
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
To find a number less than 100 that is divisible by 2, 5, and 9, we need to find the least common multiple (LCM) of these three numbers. The LCM of 2, 5, and 9 is 90. Therefore, the number less than 100 that is divisible by 2, 5, and 9 is 90.
90
90
To determine if the number 23,456,910 is divisible by 90, it must be divisible by both 9 and 10. A number is divisible by 10 if it ends in 0, which 23,456,910 does. To check for divisibility by 9, the sum of its digits (2 + 3 + 4 + 5 + 6 + 9 + 1 + 0 = 30) must be divisible by 9, which it is not. Therefore, 23,456,910 is not divisible by 90.
==yes. 90 is divisible by 3 and 9==
90
90
A number that is divisible by both 5 and 9 must be a multiple of their least common multiple (LCM). The LCM of 5 and 9 is 45. Therefore, any multiple of 45, such as 45, 90, or 135, will be divisible by both 5 and 9.