Q: Is a b

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A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C

A - B = A + (-B) A - B = A + (-B) A - B = A + (-B) A - B = A + (-B)

a < b → a - a < b - a → 0 < b - a → 0 - b < b - a - b → -b < -a → if a < b then -b < -a which can also be expressed as -a > -b

-b/(b-a) ? Multiply both top AND bottom by -1 : +b/(-b+a) which is b/(a-b)

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A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C