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Q: Is any 2 digit number with 2 identical digits divisible by 11?

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The 2-digit multiples of 11 all have identical digits.

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I

There is no number, no matter the number of digits, that is only divisible by 2.

-8

987652431

If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.

4 and all of its multiples are divisible by 4. They end in even digits. No number that ends in an odd digit is divisible by 4.

the answer is 95

If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.

A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.

The largest 5-digit number divisible exactly by 99 is 99990.

12 or 24

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