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Yes. Suppose you are multiplying two even numbers, A and B. Then make B odd by adding 1.

You can represent any even number as 2*x. So let's rewrite A*B as (2*x) * (2*y +1)

Which is 2*x*2*y + 2*x

which is 2*(x*2*y+x)

Which is of the form 2*(something) which has to be even.

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