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Any 4 from 8 is a permutation, solved by the use of factorials:

8!/((8-4)! x 4!) which simplifies to (8 x 7 x 6 x 5)/(4 x 3 x 2) ie 70 different ways.

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Q: Is how many ways can you choose 4 Cd's from a stack of 8Cd's a combination or permutation?
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