4f
3 (n + 7) = 16
n/2 + 6 = n/3 so 6 = n/3 - n/2 = 2n/6 - 3n/6 = -n/6 and so n = -36
3 6
That question has no answer since n must equal 3 and if you substitute n in 3n-2, you will see that it does not equal 3, it equals 7.
The first quantum number is the principal quantum number, denoted by "n." In aluminum, the 3p1 electron would have a principal quantum number of n = 3, since it is in the third energy level orbiting the nucleus.
n = 3
4f
3s has a principle quantum number of n=3 5s has a principle quantum number of n=5
3
3P
The four quantum numbers of arsenic are: Principal quantum number (n): 4 Azimuthal quantum number (l): 3 Magnetic quantum number (ml): -3 to +3 Spin quantum number (ms): +1/2 or -1/2
it means the major level of orbital like 2S1, the 2 is the quantum number 3D4, the 3 is the quantum number
The quantum numbers for the seventeenth electron of Argon would be n=3 (principal quantum number), l=1 (azimuthal quantum number), ml=0 (magnetic quantum number), and ms= -1/2 (spin quantum number).
32. The formula is 2n2 where n is the principal quantum number
In an atom, the number of electrons with quantum number n equals 2 is determined by the formula 2n^2. For n = 2, the maximum number of electrons is 2(2)^2 = 8.
There are a total of three p orbitals for an atom with principal quantum number n = 2: px, py, and pz. These orbitals are oriented along the x, y, and z axes.