it is greater than becuase lhalf x is half off of x so x is greater
2328.31286 cm2
The area would be 32*pi miles squared. The perimeter would be 16*pi miles.
i need the answer asap plz
It is 27.49 units.
it would be the diameter of the smaller circle times sqrt 2
In a semicircle, the diameter is the straight line. It is also equal to double the radius, and that property allows it to be used when calculating area and circumference.
A semicircle is 1/2 of a circle. Find the area with the diameter you are given as if you had a whole circle, then divide that answer by 2 to get the area of the semicircle.
25
2328.31286 cm2
A semicircle is half a circle, so its area is half that of a circle: radius = 1/2 diameter = 22 ÷ 2 = 11 area = 1/2πr2 = 1/2π112 ~= 190 sq in
The diameter of the circle is 21.4 feet, approx.
Diameter of semicircle = 1 Area of semicircle = Pi/8 Area of triangle = 0.25 Area outside triangle = (Pi/8) - 0.25 = 0.1427 (rounded to 4th decimal).
A semicircle is half of a circle, formed by cutting a circle along its diameter line. It has the same curved edge as a circle but only covers half the area. The formula for the area of a semicircle is 1/2 times π times the radius squared.
It can have any value up to 392 square cm.
Twice as big.
These windows could get extremely large, but let's play with Andersen Windows' catalog. If you build a Norman window using Andersen's largest semicircle window, which is six feet wide, and their tallest twin double-hung window, which is 6'4" high, you get an area of 52.11 square feet.
Is the 30ft the radius or the diameter. The area of a circle = Pi x (radius squared), so, if the diameter is 30ft, making the radius 15ft, the area would be Pi x(15 squared) square feet, and the area of its semicircle would be half of that, so the area required = Pi x (15 squared) divided by 2 = 353.429 sq ft On the other hand, if the diameter is 15ft, making the radius 7.5ft then the area required = Pi x (7.5 squared) sq ft for the full circle and half as much for the semicircle = 88.3573 sq ft As an extra; you will find that the area of the smaller semicircle is exactly one quarter of that of the larger semicircle, and I wonder if you can reason out why that is so.