No. Each one of them is smaller than 90 and so cannot be divisible (not divible!) by 90.
90
90. all the numbers from 10 through 99
-89
180
50 It is 40 more than 10 and 40 less than 90 To find a halfway point (which is also the average), add the numbers together and divide by 2. 10 + 90 = 100 and 100 / 2 = 50
90, 180, 270, 360, & 450
Any of their multiples
10 and 45. 10=5*2 10+45=55 45*2=90 45=5*9 10*9=90
12 10 10 10
As written, no. But I'm pretty sure you meant to ask that the other way around. Out of that list, 416 is divisible by 2 and 4.
40 and 50
There are 180. 10 through 99 and -10 to -99.
Yes. 906 / 2 = 303.
40 and 50
90
1, 2, 4, 11,22
45 and 10