No, it is not a redox reaction. None of the oxidation numbers changes during the reaction. You have to determine the oxidation number for each element and see if it changes from reactant side to product side. If the oxidation number doesn't change, it is not a redox reaction.
Sodium (Na) has been reduced.
I cannot answer this question.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
In the redox reaction, silver (Ag) has been reduced because it gains electrons in forming solid silver (Ag) from silver nitrate (AgNO3).
In the redox reaction AgNO3 + NaNO3 + Ag, silver (Ag) is reduced from Ag+ to Ag with the gain of one electron. Therefore, one electron is transferred in this reaction.
Silver (Ag)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
The reaction of Al and FeCl3 to form Fe and Al2O3 is a redox reaction, specifically a single replacement reaction where Fe gains electrons (reduction) and Al loses electrons (oxidation). The release of energy indicates that it is an exothermic reaction.
Silver cations are reduced.
In this redox reaction, silver nitrate (AgNO3) is reacting with sodium (Na) to form sodium nitrate (NaNO3) and silver (Ag). The sodium is getting oxidized (losing electrons) while the silver in silver nitrate is getting reduced (gaining electrons).
The reaction between silver nitrate (AgNO3) and zinc (Zn) is a single displacement reaction, specifically a redox reaction. The zinc metal displaces silver from the silver nitrate solution, forming zinc nitrate and silver metal.
In the given redox reaction, silver nitrate (AgNO3) reacts with sodium nitrate (NaNO3) and elemental silver (Ag). The element that has been reduced is silver (Ag) because it is being converted from its ionic form (Ag^+) in AgNO3 to its elemental form (Ag). Reduction involves the gain of electrons, and in this case, Ag^+ gains an electron to become neutral Ag.