NO!!! It is an exponential function.
2 = 2^(1)
4 = 2^(2)
8 = 2^(3)
16 = 2^(4)
32 = 2^(5)
...
2^(n)
If n = x on the co-ordinate axes, that is you go along 1,2,3,4,5 etc., the 'y' values (2,4,8,16,32, etc.,) , do NOT go up in a straight line, but an ever steepening gradient. Hence it is NOT a linear function.
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What is the value of the 8th term of the sequence 4, 8, 16, 32,?what is the answers?1,024,512,128or2,048.
It is 32768.
You are multiplying each number in the sequence by -2. Therefore, the next number in the sequence after 32 is -64.
The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.
-64