The square root of seven is a real number, but it is not a whole number.
Yes. The square root of 49 is 7.
Well, first let's define a "real number." A real number is any number that's not imaginary. It can be rational or irrational. The square root of 7 is 2.64575131... and it goes on forever. This means it cannot be written as a simple fraction. We can give an estimate of the square root of 7 in a fraction form, but this is not the exact result. So, the square root of 7 is a irrational number.Since a real number can be irrational or rational, yes, the square root of 7 is a real number.
Yes.
Yes although it is an irrational number
Nothing. You cannot have a square root of a negative number. The square root of negative one is called i, but i is an imaginary number. It does not exist and does not follow the properties of real numbers. (For example, if a and b are positive, then the square root of a times the square root of b is the square root of ab. But the square root of -7 is not the square root of 7 times i.)
the square root of -28 is the square root of -1 time the square root of 28. The square root of -1 is not a real number, it is represented by i. The square root of 28 is the square root of 4 times the square root of 7 (4*7=28) The square root 4 is equal to 2, and the square root of 7 cannot be simplified.The answer is 2i√7.
no, 28 has no whole square root; the square root of 49 is 7
A square root is a number that is multiplied by itself to get the number here's an example. 7 is the square root of 49 (7*7=49)
the square root of 49 equals 7
The square root of 49 is 7 or -7.
It is: the square root of 7 times the square root of 7 = 7
yes. Examples: the square root of 7 times the square root of 7 = 7 the square root of 7 times one over the square root of 7 = 1