Answer 1:
Yes, there are infinitely many numbers divisible by all numbers 1 though 9. You can find the smallest such number by multiplying all of the numbers 1 through 9 together:
1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 = 9! = 362,880
362,880 and any number that is a multiple of 362,880 are divisible by every number 1 to 9.
Answer 2:
Actually, I believe 2,520 is the smallest number divisible by 1-9.
Multipying 1-9 does give you 362,880, and that is a good way of always getting an answer. But it's not always the smallest answer.
12
All the numbers, I suppose!
2940 is an even number and all even numbers are divisible by 2. It is also divisible by 1, by 2940, and by all of its other factors.
All multiples of 1, which is an infinite number.
1, as are all numbers. oh, and 17.
All numbers are divisible by 1. So, apart from the number 1, all numbers are divisible by another number. These numbers are therefore prime or composite.
All numbers are divisible by 1.
All numbers are divisible by one.
All numbers are divisible by one.
of course all numbers are divisible by 1 expect 0 and numbers that have decimals
16
12
All the numbers, I suppose!
All numbers are divisible by 1.
2940 is an even number and all even numbers are divisible by 2. It is also divisible by 1, by 2940, and by all of its other factors.
143 is not a prime number; it is divisible by 11 and 13.Incidentally, it is divisible by 1; all numbers are.
All multiples of 1, which is an infinite number.