They are identities because they are true for ALL values of w and x.
13x60minus w
13 multiplied by the amount (quantity) 60 minus w is written mathematically as 13(60-w).
To evaluate t-7 over w for t equals -3 and w equals -2, we substitute -3 for t and -2 for w in the expression. This gives us (-3) - 7 over (-2), which simplifies to -10 over -2. Further simplifying, we get 5 as the final result.
82
They are identities because they are true for ALL values of w and x.
13x60minus w
That depends what the value of w is.
13 multiplied by the amount (quantity) 60 minus w is written mathematically as 13(60-w).
If: w-7 = 11 Then: w = 18
(w - 2)(w + 2)(w^2 + 4)
Type this: ((w^2)/(w-6))((w^2-4w-12)/(w^2-3w) Into wolframalpha.com. It will give you the answer (too much for this box).
13(60 - w)
13(60 - w)
L = P/2 - W.
It is a linear equation in a single variable, w.
6493 - 2189 = 4304