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r * t = d We know that the distance was the same. So, where x = the rate on the way to his friend's house: Trip there = Trip back x * (3 hours) = (x-2) * (4 hours) -or- 3x = 4(x-2) 3x = 4x - 8 8 = x He was traveling 8 mph on the way there. The distance was 24 miles (8 mph * 3 hours. He was traveling 6 mph on the way home, which makes sense because it would take 4 hours to travel 24 miles while traveling 6 mph.

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Q: Jim rode 3 hours to his friend's house the return trip home took 4 hours because he was going 2mph slower how fast was he traveling to his friend's house how fast was he traveling on the way home?
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