what exactly is your question? If you want to know where is this school, it is located in near Tiruchendur, in the district of Tuticorin, Tamil Nadu, India. This school is <1km from the Kurumbur Railway station and about 15 kms from Tiruchendur.
None. Ond day is 60 secs x 60 mins x 24 hrs = 86400 sec 56000 sec is approx 15 hrs and 33 mins.
2mins : 5 sec = 2x60 sec : 5 sec = 120 sec : 5 sec = 120:5 = 120/5 = 24
You will have to figure out how many leap years. In this answer, I figured it based on if the leap year was on the 1st year. Then you would have one in your 1st, 5th and 9th year. Also figured that a year is 365 days and a leap year is 366 days. There are 31,536,000 sec in a year and 31, 622,400 sec in a leap year. 365dys x 24 hrs = 8760hrs a year 366dys x 24 hrs = 8784 hrs a leap yr 8760hrs x 60min=525,600min/yr 8,784hrs x 60min=527,040min/lp yr 525,600mins x 60sec=31,536,000sec/yr 527,040min x 60sec=31,622,400 sec/lpyr 31,536,000 x 8 regular years =252,288,000secs in 8 regular years 31,622,400 x 3 leap years = 94,867,200sec in 3 leap year 252,288,000sec +94,867,200sec = 347155200 347,155,200secs in 11 years if there are 3 leap years
32 min 9 sec 40 min 10 sec adding gives... 71 min 19 sec 1 hr 11 min 19 sec. ■
300 sec
1 day = 24 hrs, so 7 days = 168 hrs Each hour is 3600 sec, so 168 hrs is 604800 sec Hence 7days = 168 hours = 604800 seconds
366 days x 24 hrs/day = 8784 hrs 8784 hrs x 60 min/hr = 527040 min 527040 min x 60 sec/min = 31622400 sec
2.5 hrs = 150 minutes 150 minutes = 9000 seconds
saint andrws rc sec school smithycroft sec school lochend sec school
None. Ond day is 60 secs x 60 mins x 24 hrs = 86400 sec 56000 sec is approx 15 hrs and 33 mins.
SMSV. Hr. Sec School was created in 1895.
10 hrs. 10 mins 15 sec. as of 1:48 and 52 sec. pm on nov. 29 2008
144 hrs or 8640min. or 518,400 sec.
592/70= 8.45...hrs 8 hrs 27 min 25.714 sec
It would take 10.82857143 hrs. ( 10 hrs 49 mins. 42.85714296 sec. ).
It beats about 72/sec; so 72X60X4=17280.
19 hrs 42 mins 28 sec