I don't know exactly what type of formula you are looking for..... But, if you let n = # of term.... then the rule would be 3^(n - 1)
The answer is 1,3,9,27,81. 81*1=81 3*27=81 9*9=81 27*3=81 81*1=81
81. Each number is the previous number times three. 3 x 27 = 81.
81= 1, 2,9, and 81 27= 1, 3,9, and 27
1, 3, 9, 27, 81. 1 x 81 = 81, 3 x 27 = 81, 9 x 9 = 81.
Factors of 81: 1, 3, 9, 27, 81 Factors of 27: 1, 3, 9, 27 GCF (81, 27) = 27
Multiply each term by 3 to get the next one.
1/3 or one third 27/81 divide both by 27 27/27 = 1 27/81 = 3 Answer: 1/3
1, 3, 9, 27 1, 3, 9, 27, 81 9, 27 and 81 are composite.
The multiples of 81 are infinite. The factors of 81 are: 1, 3, 9, 27, 81.
The factors of 27 are: 1, 3, 9, 27 The factors of 81 are: 1, 3, 9, 27, 81
The factors of 27 are: 1, 3, 9, 27The factors of 81 are: 1, 3, 9, 27, 81
1, 3, 9, 27, 81, -1, -3, -9, -27, -81