9 years
Mike is 12. Mary is 4. In 4 years, Mike will be 16 and Mary will be 8. So Mike will be twice as old as she is in four years.
9
Let's say that 10 years ago Ben was x years old, and Mike was 7x years old.Now Ben would be x + 10 years old, and Mike 2(x + 10) or 7x + 10 years old.So we have (Mike age):2(x + 10) = 7x + 102x + 20 = 7x + 10 (subtract 2x and 10 to both sides)2x - 2x -10 + 20 = 7x - 2x - 10 + 1010 = 5x (divide by 5 to both sides)2 = x (Ben's age 10 years ago)So that Ben is 12 years old now, and Mike is 24 years old (as you see Mike was a very young father, 14 years old).
Mike is 30; Bill is 2. m = 15b m - 28 = b 15b - 28 = b 14b = 28 b = 2 m = 15(2) = 30
Mikey, Mike & Ike
9
9
Mike is 12. Mary is 4. In 4 years, Mike will be 16 and Mary will be 8. So Mike will be twice as old as she is in four years.
9
12,4...16,8
Mary is 4 years old. [A+]
Twice
Write and solve two simultaneous equations. a = Mary's age b = Mike's age Age now: b = 3a Age in 4 years: b + 4 = 2(a + 4)
mike is 2 years older than david
He has one brother, Mike, who is 2 years younger than him.
Leo must be 18. If Leo is twice as old as martin and three times older than mike and the sum of the ages is 33, then martin would be 9 and mike would be 6, making Leo 18.
Twice Once in 1989 and 2nd time in 1996