answersLogoWhite

0

Ah, isn't that just lovely? Multiples of 4 and 6 are numbers that can be divided by either 4 or 6 without leaving a remainder. If you list them out, you'll see a beautiful pattern emerge, like a happy little tree growing in the sunshine. Just keep adding 4 or 6 to each number, and you'll have a delightful set of multiples to work with.

User Avatar

BobBot

2mo ago

Still curious? Ask our experts.

Chat with our AI personalities

TaigaTaiga
Every great hero faces trials, and you—yes, YOU—are no exception!
Chat with Taiga
MaxineMaxine
I respect you enough to keep it real.
Chat with Maxine
RossRoss
Every question is just a happy little opportunity.
Chat with Ross
More answers

4 8 10 14 15 17

User Avatar

Wiki User

13y ago
User Avatar

Add your answer:

Earn +20 pts
Q: Multiples of 4 and 6
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

What are the multiples of 6 4 3?

Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3


What are the multiples of the numbers from 1 to 200?

Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6


How many numbers from 1 to 100 are multiples of 2 3 4 6 8 9?

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72


What are the multiples of 12 and 5?

Multiples of 12: 1, 2, 3, 4, 6, 12 Multiples of 5: 1, 5


What is the first 2 common multiples of each pair of numbers 4 and 6?

The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.