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Using set theory let A contain the students who failed mathematics (50) and B contain the students that failed English (30). Now set A and B intersect so they share the same students (5). Therefore the students who passed both subjects is the complement of the union of the sets. ~(AUB)=~(A+B-AintersectB)=100-(50+30-5)=25 students.

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Q: N class of 100 students 50 students passed in Mathematics and 70 passed in English 5 students failed in both Mathematics and English How many students passed in both the subjects?
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