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Assuming the sequence does not merely skip from 13 to 49, and instead carries on in the same pattern, the sequence proceeds thus:

1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49.

This is thirteen terms. The formula for finding these terms is 4x-3.

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Anonymous

4y ago
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Q: Number of terms in the following arithmetic sequence 1 5 9 13 49?
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