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gghg a regular polygon has a 32 sides. calculate the size of each interior angle.

Q: Number of triangles in a 32 side polygon?

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The sum of the interior angles of a polygon is 2n - 4 right angles, where n is the number of sides.(2 x 32) - 4 = 60 right angles = 60 x 90 = 5400Â° .

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A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16

It's not. 32 is an even number.

the greater number is 32.

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A 32 sided polygon is also called a triacontadigon (or triacontakaidigon) or 32-gon has 20 triangles and 12 pentagons.

30 of them

A polygon with 32 sides is known as a triacontakaidigon.

38 diagonals

A triacontakaidigon is a polyhedron with 32 sides. If the sides are all triangles, then there are 32 triangles in a triacontakaidigon, but a triacontakaidigon does not need to have triangular shaped sides.

The regular 16 sided polygon will consist of 16 congruent isosceles triangles with equal sides of 5.125830895 cm by using the sine rule with equal base angles of 78.75 degrees and an apex angle of 22.5 degrees opposite side of 2 cm. Area of polygon: 0.5*5.125830895^2 *sin(22.5)*16 = 80.43743186 square cm

(5400+360)/180 = 32 sides

The sum of the interior angles of a polygon is 2n - 4 right angles, where n is the number of sides.(2 x 32) - 4 = 60 right angles = 60 x 90 = 5400Â° .

It has 32 lines of symmetry.

32

Infinitely many. Consider a regular polygon with n sides where n > 2. Let x = 32/n. Then the perimeter of the polygon is n*(32/n) = 32.

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