numbers that are multipied together to give a product are called factors
Multiplicands are multiplied together to give the product.
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
The only integer solution to this question is 2 and 2 which give 4 when they are added together or multiplied together. If you do not limit yourself to integers, then any pair of numbers, x and x/(x-1) will fit the bill where x not = 1. Their sum and product are x^2 / (x-1).
1 and 0
numbers that are multipied together to give a product are called factors
Multiplicands are multiplied together to give the product.
80*9= 720
3,5and11
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
The multiplicand and the multiplier.
11
5x15 = 75
-21
301 is a prime number. Therefore only two numbers multiplied together to give 301 is itself and 1.
The only integer solution to this question is 2 and 2 which give 4 when they are added together or multiplied together. If you do not limit yourself to integers, then any pair of numbers, x and x/(x-1) will fit the bill where x not = 1. Their sum and product are x^2 / (x-1).