Because the freezing point of water is zero-C but 32-F. The C-temp tells you (how many C-degrees above freezing it is), because C starts at zero. But the F-temp has to be 32 more than (how many F-degrees above freezing it is), because F starts at 32, not at zero.
ex+f = c -dx ex+dx = c -f x(e+d) = c -f x = c -f/(e+d)
You plug in the (degrees F), do the arithmetic, and wind up with the (degrees C).
°F to °C: [°C] = ([°F] − 32) × 5⁄9°C to °F: [°F] = [°C] × 1.8 + 32
a. 40 THE ANSWER IS 40 b. x c. 20 d. f(x)
F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50
288 degrees C = 540.4 degrees F. F = 1.8*C + 32 Therefore, where C = 288, F = (288*1.8) + 32 = 518.4 + 32 = 540.4
What does a F and a D- queal out as
-15°C = 5°F-15°C multiplied by 1.8 +32 = 5°F
Because the freezing point of water is zero-C but 32-F. The C-temp tells you (how many C-degrees above freezing it is), because C starts at zero. But the F-temp has to be 32 more than (how many F-degrees above freezing it is), because F starts at 32, not at zero.
C = (F - 32) x 5/9 F = C x 9/5 + 32
0 degrees Celsius is 32 degrees Fahrenheit
7 c = 32 + 7 x 9/5 F = 32 + 12.6 F = 44.6 F
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440.6 rounded up. The formula for F to C is (F-32) x 5/9=C, and to convert from C to F, (C x 9/5) +32=F
0 Degrees Centigrade/Celsius is 32 Degrees Fahrenheit