Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
The composite numbers in that list are 22 and 36 - you know they are composite, because they are even numbers. The other numbers are odd and prime.
37 = 37. No other number (prime number or otherwise) is equal to 37.
37 34 = 17 x 2 35 = 7 x 5 36 = 18 x 2
36, 37, 38 36+37+38=111
All of them except for 31 and 37 which are prime numbers
37
You can only divide prime numbers by 1 and by themselves. 35 can be also divided by 5 and by 7, so, not a prime. 36 can be also divided by 2, 3, 4, 6, 9, 12, 18, so, not a prime. 37 is a prime because it cannot be divided by any other number than 1 and itself.
The prime numbers between 35 and 45 are 37, 41, and 43.
The answer is c. 37 35 = 5 x 7 36 = 2 x 2 x 3 x 3 39 = 3 x 13
The prime numbers are 19, 29, 31, and 37. The composite number is 35.
Just 37.
There are 4 prime numbers between 36 and 49. 37, 41, 43, and 47.
There is only one and it is 37 whereas 32 33 34 35 36 38 39 and 40 are composite numbers
It is 37 because it has only two factors which are itself and one
66
37, 41, and 43 are prime numbers.