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Let a be the first number and b the second number then,

(1) a = 8 + 2b and (2) a + b =123

From (2) a = 123 - b substituting for a in (1) gives :-

123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓.

and substituting for this in (2) gives :-

a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔.

So, a = 84⅔ and b = 38⅓

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Q: One number is 8 more than twice the second number The sum of the numbers is 123 Find the numbers?
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