Let a be the first number and b the second number then,
(1) a = 8 + 2b and (2) a + b =123
From (2) a = 123 - b substituting for a in (1) gives :-
123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓.
and substituting for this in (2) gives :-
a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔.
So, a = 84⅔ and b = 38⅓
The third number is 112, the numbers are 86, 86, 112, 172
Let the numbers be x and y If: x+2y = 3 and 2x+y = 27 Then the simultaneous equations work out as: x = 17 and y = -7
11,33
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
18 and 6
The third number is 112, the numbers are 86, 86, 112, 172
Let the numbers be x and y If: x+2y = 3 and 2x+y = 27 Then the simultaneous equations work out as: x = 17 and y = -7
11,33
joan decided to use her calculator to find the sum of the first 15 counting numbers instead of the formula. By mistake she entered 16 numbers. She entered one number twice . Her answer was 4 more than a perfect square number. Which number did joan enter twice?
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
18 and 6
a=58.4615 b=5.2308 c=41.3076
Let x represent the first number; 2x - 3 then represents the second number. x + 2x - 3 = 75 3x = 78 x = 26 2x - 3 = 49 So the numbers are 26 and 49.
Number one = x Number two = y Number three = z x + y + z = 26The second number is twice the first. y = 2x The third number is 6 more than the second. z = y + 6 z = 2x + 6 x + 2x + (2x + 6) = 26 5x = 20 x = 4 Number one = 4 Number two = 8 Number three = 14
If the second number is a multiple of the prime number, than the LCM is the second number. If the second number is not a multiple of the prime number, then the two numbers are relatively prime, and the LCM is the product of the two numbers.
42,89
There aren't any whole numbers that satisfy this.