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Optimum value of y equals -3 times x-5 tothepowerof2 plus 4 .. show work?
Wiki User
∙ 15y ago
So that's y=-3(x-5)^2 + 4? Okay, so I don't know what you mean by optimum value, but that's going to be y= -3x^2 + 10x - 71, which is an upside down parabola. The maximum of said parabola is going to be where the derivative equals 0, so -6x + 10 = 0, so x= 5/3. Then the corresponding y value is 25/3 - 71... I'll let you do that last bit of math. The maximum of the parabola is then at the point (5/3, 25/3 - 71).
Wiki User
∙ 15y ago
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