p --> q and q --> p are not equivalent
p --> q and q --> (not)p are equivalent
The truth table shows this.
pq p --> q q -->(not)p
f f t t
f t t t
t f f f
t t t t
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Square D type HOM is interchangeable with Siemens type QP
112
Yes. Suppose x divides y then there exist an integer p such that y = px. Suppose y divides z then there exist an integer q such that z = qy. Therefore z = q*px = qp*x Since p and q are integers then pq is an integer and therefore x divides z. That is to say: if x divides y and y divides z, then x divides z.
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CAPITAL LETTERS: F, G, J, N, P, Q, R, S, Z these may or may not have: B, K, L small letters: a, b, d, e, f, g, h, j, k, p, q, r, s Note: db and qp can have a line of symmetry between the letters