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You can't prove this proposition because it isn't true.

Proof: the fifth root of 1024 is 4, and 4 is not irrational.

It is true that, when N is an integer greater than 1, the Nth root of any integer greater than 1 is either an integer orirrational, but that's a different matter.

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Q: Proof of Nth root is irrational?
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Is the square root of 32 an irrational or a rational number?

The square root of a positive integer can ONLY be:* Either an integer, * Or an irrational number. (The proof of this is basically the same as the proof, in high school algebra books, that the square root of 2 is irrational.) Since in this case 32 is not the square of an integer, it therefore follows that its square root is an irrational number.


Why is the square root of 33 irrational?

Most high school algebra books show a proof (by contradiction) that the square root of 2 is irrational. The same proof can easily be adapted to the square root of any positive integer, that is not a perfect square. You can find the proof (for the square root of 2) on the Wikipedia article on "irrational number", near the beginning of the page (under "History").


Is the square root of a 143 a irrational number?

Yes. The square root of a positive integer can ONLY be either:* An integer (in this case, it isn't), OR * An irrational number. The proof is basically the same as the proof used in high school algebra, to prove that the square root of 2 is irrational.


Why is 3 square root of 2 is irrational?

sqrt(2) is irrational. 3 is rational. The product of an irrational and a non-zero rational is irrational. A more fundamental proof would follow the lines of the proof that sqrt(2) is irrational.


How can you proove that root 3 and root 5 are irrational?

See http://mathforum.org/library/drmath/view/52619.html for a proof of the irrationality of sqrt(3). The proof that sqrt(5) is irrational is identical (substituting 5 for 3 in the proof).


Why is there no direct proof of the infinity of primes naturals sqrt2 after 2000 years?

A direct proof of the infinity of primes would require what is essentially a formula to calculate the Nth prime number; such a formula isn't even guaranteed to exist. It's possible to formulate a proof of the infinity of primes that would be, in a sense, direct. A direct proof that the square root of 2 is irrational is impossible, because the irrational numbers aren't defined in any direct way - just as the real numbers which aren't rational. So to prove that the square root of 2 is irrational, we have to prove that it's not rational, which requires indirect techniques.


Is the square root of 3 rational?

Root of '3' is NOT rational. It is an IRRATIONAL Number. To 9 d.p. it is sqrt(3) = 1.732050808.... NB THE square roots of prime numbers are irrational , just like 'pi = 3.141592....'. NNB A irrational number, put casually, is a number were the decimals go to inifinty and there is no regular order in the number2.


Is they sqare root of 94 irrational or irrational?

The square root of 94 is an irrational number


Is the square root of 200 rational or irrational?

The square root of 200 is irrational.


Give a proof that the square root of 3 is an irrational nu?

It is a prime number that has only factors of itself and one therefore it is an irrational number like all prime numbers are.


Is the square root of 14 rational or irrational number?

Search for the proof for the irrationality of the square root of 2. The same reasoning applies to any positive integer that is not a perfect square. In summary, the square root of any positive integer is either a whole number, or - as in this case - it is irrational.


Is the square root of 6 irrational?

Answer: The square root of 6 is irrational. Reason: Just try to convince it otherwise, you will see their is no way to deal with it since it becomes angry and irrational! But seriously, you can't write it as a fraction of the from p/q with p and q being integers so yes it is irrational. The proof would be easy by contradiction.