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Solving algebraically, set the variable C as Carlos' age

Raul's age = 2C + 5 (5 years more than twice as much)

The sum of C + (2C+5) is 101

3C + 5 = 101.

3C = 96

C = Carlos = 32

2C + 5 = Raul = 69

32 + 69 = 101

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Q: Raul is 5 years older than twice Carlos' age the sum of their ages is 101 how old is Carlos?
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