Reduce the fraction w2 plus 5w plus 6 over w2-w-12?

Answer 1

Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!

Answer 2

(w² + 5w + 6) / (w² - w - 12)

= [(w + 2)(w + 3)] / [(w - 4)(w + 3)]

= (w + 2) / (w - 4)