P=2l+2w, so the perimeter is 21 yards.
Perimeter: 20+16+20+16 = 72 feet
The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the room has a length of 3.2 meters and a width of 2.5 meters. To find the perimeter, you would add up all four sides: 3.2m + 2.5m + 3.2m + 2.5m = 11.4 meters. Therefore, the perimeter of the room is 11.4 meters.
Perimeter = 38+17+38+17 = 110 units of measurement
Perimeter = 2+2+3+3 = 10 feet
60 feet or 10 yards - without the aid of a calculator !
The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the room is 12 feet long and 10 feet wide. To find the perimeter, you add the length of all sides: 12 + 12 + 10 + 10 = 44 feet. Therefore, the perimeter of the room is 44 feet.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
To find the perimeter of a rectangle, you add up all the sides. In this case, the room is 5 meters long and 3 meters wide. So, the perimeter would be 5 + 5 + 3 + 3 = 16 meters.
2*(length + width) = 54 feet.
P=2l+2w, so the perimeter is 21 yards.
Perimeter: 20+16+20+16 = 72 feet
Perimeter = 12+12+7+7 = 38 inches
15ft+12.5ftft+15ft+12.5ft=55ft P=55ft
A possibility: 2 yards by 3 yards
That's a nice problem! The room is 5-ft long and 4-ft wide.
l = 2w perimiter = 96 = 2l + 2w = 4w+2w = 6w = 96 w = 16 l = 32