He would have 2 quarters and 8 dimes. (2 x 0.25) + (8 x 0.10) = 0.50 + 0.80 = 1.30
Chen has 8 nickels, 2 dimes, and 6 quarters.
4 Qs 12 Dimes 20 Nickles
7 quarters 2 dimes 4 nickels
In total, 3 quarters and 10 dimes would amount to $2.50. This is because each quarter is worth $0.25 and each dime is worth $0.10. Therefore, 3 quarters would be $0.75 and 10 dimes would be $1.00, making the total $1.75 + $1.00 = $2.50.
7 nickels, 4 dimes, 3 quarters
Chen has 8 nickels, 2 dimes, and 6 quarters.
11 ways. You need an even number of quarters and the rest dimes; so 0,2,4,6,8,10,12,14,16.18 or 20 quarters with the balance dimes in each case.
4 Qs 12 Dimes 20 Nickles
It's not possible to give a specific answer without knowing how the numbers of each coin are related. Otherwise there are hundreds of possible combinations; for example278 quarters, 0 dimes, 0 nickels277 quarters, 0 dimes, 5 nickels277 quarters, 1 dime, 3 nickels277 quarters, 2 dimes, 1 nickel276 quarters, 0 dimes, 10 nickelsand so on
7 quarters 2 dimes 4 nickels
70 - 30 = 40, 40/2 - 20, so there are 20 dimes and 50 quarters
12 quarters 6 dimes
30 quarters equals $7.50 42 dimes equals $4.20 That adds up to 72 coins with a value of $11.70
Sally has 76 Quarters and 24 Dimes. I hope that I am not doing your homework for you =)
In total, 3 quarters and 10 dimes would amount to $2.50. This is because each quarter is worth $0.25 and each dime is worth $0.10. Therefore, 3 quarters would be $0.75 and 10 dimes would be $1.00, making the total $1.75 + $1.00 = $2.50.
7 nickels, 4 dimes, 3 quarters
it took a few mins to figure it out but its 36 quarters and 39 dimes