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Assuming the math club had 15 sixth graders, 12 seventh graders, 13 eighth graders and no other members, then:

There are 15 + 12 = 27 students that are sixth or seventh graders.

There are 15 + 12 + 13 = 40 members.

So the fraction that are sixth or seventh graders is 27/40.

Using long division, 27/40 = 0.675 = 67.5%

So 67.5% of the math club members are sixth or seventh graders.

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Q: School has 15 sixth graders 12 sevenths and 13 eight graders what percentage of math club members are either sixth or seventh graders?

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five seventh

4 1/7 (four and one seventh).

First find one seventh, by dividing 14 by 7. 14 / 7 = 2 One seventh = 2 Two sevenths = 4

Four-Sevenths would be equal to 15.5714286.

three-seventh of a number, increased by fourteen

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five seventh

40%

3 and 1 seventh :)

most of the time, i think it's because the seventh graders are older than the sixth graders (obviously) so the seventh graders think they can date (or whatever) whoever they want in sixth grade, or lead them on. or at least, that's what i think. Xd why would a 7th grader want to date a 6th graders and 6th graders shouldnt be dating

with 60 other different 7th graders

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DOTA

They could if they wanted to. But the seventh grader might be more mature and might expect more from the relationship.

six seventh = 0.67 Answer = 3 x 0.67 = 2.01

4 1/7 (four and one seventh).

First find one seventh, by dividing 14 by 7. 14 / 7 = 2 One seventh = 2 Two sevenths = 4

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