The multiples of 4 are numbers that can be divided evenly by 4. To find all the multiples of 4 from 1 to 1000, we can start by finding the first multiple of 4, which is 4. Then we can continue adding 4 to find the rest of the multiples. The multiples of 4 from 1 to 1000 are: 4, 8, 12, 16, ... , 996, 1000.
All multiples of 12, such as 120, 600, 660.
All of its multiples from 3 to 999
105add 7repeatuntil you reach 994
The first multiple of 3 is 3; the last multiple of 3 below 1000 is 999. (This can be determined by dividing 1000 by 3, ignoring the remainder, and then multiplying that number by 3 to determine the largest multiple of 3 less than 1000.) Since 999 is 3 times 333, there are 333 multiples of 3 that are less than 1000. So, consider them by pairs: 1st and 333rd = 3 + 999 = 1002 2nd and 332nd = (2 x 3) + (332 x 3) = 6 + 996 = 1002 3rd and 331st = (3 x 3) + (331 x 3) = 9 + 993 = 1002 up to 166th and 168th = (166 x 3) + (168 x 3) = 498 + 504 = 1002 167th = 501 (which is half of 1002) In other words, since 333 is not an even number, there are (333 - 1)/2 = 166 pairs, plus that extra half of a pair. The sum of all the multiples of 3 less than 1000 is 166.5 x 1002 = 166,833. The same can be done for the multiples of 5. The first multiple of 5 is 5; the last multiple of 5 below 1000 is 995. (This can be determined by dividing 1000 by 5, subtracting 1 since it divided evenly and you need the largest multiple less than 1000, and then multiplying that number by 5 to determine the largest multiple of 5 less than 1000.) Since 995 is 5 times 199, there are 199 multiples of 5 that are less than 1000. So, consider these by pairs as well.e are 1st and 199 = 5 + 995 = 1000 2nd and 198 = 10 + 990 = 1000 up to 100th = 500 (which is half of 1000) In other words, since 199 is not an even number, there are (199 - 1)/2 = 99 pairs, plus that extra half of a pair. So, the sum of all the multiples of 5 less than 1000 is 99.5 x 1000 = 99,500. If the desired answer is the sum of all numbers less than 1000 that are either multiples of 3 or 5, then the numbers that are multiples of both 3 and 5 have been included twice - once as multiples of 3 and again as multiples of 5. So, since all numbers that are both multiples of 3 and multiples of 5 are multiples of 15, determine the sum of all the multiples of 15 and subtract it from the sum of the multiples of 3 and the multiples of 5. We can repeat the same procedure again. The first multiple of 15 is 15; the last multiple of 15 less than 1000 is 990. Since 990 is 15 x 66, there are 66 multiples of 15 less than 1000. 1st and 66th = 15 + 990 = 1005 2nd and 65th = 30 + 975 = 1005 and so on Since 66 is an even number, there are 66/2 = 33 pairs. So the sum of all the multiples of 15 less than 1000 is 33 x 1005 = 33,165. The sum of all the multiples of 3 and all the multiples of 5, but not counting them twice, is 166,833 + 99,500 - 33,165 = 233,168.
The multiples of 4 are numbers that can be divided evenly by 4. To find all the multiples of 4 from 1 to 1000, we can start by finding the first multiple of 4, which is 4. Then we can continue adding 4 to find the rest of the multiples. The multiples of 4 from 1 to 1000 are: 4, 8, 12, 16, ... , 996, 1000.
4
This question was asked and answered yesterday under: "1-1000 in roman numerals?"
All multiples of 12, such as 120, 600, 660.
All of its multiples from 3 to 999
Common multiples of 4 and 6 below 1000: Lowest common multiple of 4 and 6 is 12 All multiples of 12 number 83 from 12 upto 996 because 1000/12 equals 83....
545
Since 1000 is even, all of its multiples are even as well. Simply multiply 1000 by different integers, to gets its multiples.
6,12,18,24,30,36,42,48
The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500
All the numbers from 2 to 19 are multiples of prime numbers.
Just 99.