Hi!
Given: l is a straight line and A is a point not lying on l. AB⊥ l and C is a point on l.
To prove: AB < AC
Proof: In ∆ABC,
∠B = 90°
Since, C can lie anywhere on l (other than M)
So, AB is the shortest of all line segments drawn from A to l.
Cheers!
A circle.
There is only one line (or line segment) that can be drawn between two distince points.
Infinity
The line drawn from the center of a regular polygon and perpendicular to a side.
Chord.
That is correct. The distance from a point C to a line AB is the length of the perpendicular segment drawn from point C to line AB. This forms a right angle, creating a right triangle with the segment as the hypotenuse. The length of this perpendicular segment is the shortest distance from the point to the line.
A circle.
apothem
Apothem!
It is the perpendicular bisector
There is only one line (or line segment) that can be drawn between two distince points.
An altitude is a perpendicular drawn from a point to the opposite segment while a median is a segment drawn from a point to the opposite side such that it bisects the side.Altitudes and their concurrenceMedians and their concurrence
A perpendicular segment drawn from a vertex to the line that contains the opposite side
twenty
The perpendicular line segment construction involves creating a line segment that meets another line at a right angle (90 degrees). This is typically done using a compass and straightedge. First, a point is marked on the line where the perpendicular will intersect. Then, arcs are drawn from this point to establish two points equidistant from it, allowing the straightedge to connect these points, forming a perpendicular line.
Isotomic refers to points that have equal distance from two given points. In geometry, these points lie on the perpendicular bisector of the line segment connecting the two given points.
Drawing two tiny parallel lines over the segment will indicate that it is a congruent segment. The little arc symbol can also be drawn over the segment or the angles.