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Hi!

Given: l is a straight line and A is a point not lying on l. AB⊥ l and C is a point on l.

To prove: AB < AC

Proof: In ∆ABC,

∠B = 90°

Since, C can lie anywhere on l (other than M)

So, AB is the shortest of all line segments drawn from A to l.

Cheers!

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Q: Show that of all line segments drawn from a given point not on it the perpendicular line segment is the shortest?
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