Cannot show a picture, but visualise a right angled triangle. Then imagine one of the [acute] vertices chopped off by a line parallel to the opposite side.
You will then have a trapezium with two right angles. Very crudely, it should look like the figure below:
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it is impossible i think. BUT if u want to know go on google type in a hexagon with 3 right angles then click mages and maybe it will show u.
Draw a right angle (90o). Bisect the right angle and there will be two 45o angles. Bisect one of the 45o angles and there will be one 45o angle and two 22.5o angles. A 67.5o angle includes the 45o angle and the 22.5o angle next to it, totaling 67.5o.
An equilateral triangle is a triangle where all sides are the same length and all three angles are the same. The sum of the angles of a triangle is 180 degrees. 180 ÷ 3 = 60
the only way for a right triangle to have a line of symmetry, is if the legs of the triangle are congruent. Or you can show that both non-right angles are congruent (45 degrees). you may also prove that the altitude of the triangle bisects the hypotenuse or that it equals 1/2 of the hypotenuse.
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The picture you are looking for is a parallelogram.
I need angles both sides of a picture, where I can fix a picture of princess Karen H. Chaer
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To prove a quadrilateral is a trapezium using similarity, you need to show that one pair of opposite sides is parallel. You can do this by demonstrating that the triangles formed by the non-parallel sides and the segments connecting the endpoints of the parallel sides are similar. If the angles formed by these triangles are equal (due to parallel lines creating corresponding angles), then the sides will be proportional, confirming the similarity. Thus, if you establish similarity in this way, you can conclude that the quadrilateral is a trapezium.
A regular pentagon doesn't have any right angles ! See related link.
____________ / | /_____________ | Crappy drawing, I know, but a right trapezoid has two right angles(right side of picture), and two supplimentary non-right angles(left side of drawing). This is still a trapezoid because in order to be a trapezoid, there must be one and only one pair of parallel lines, and four sides. That's it, thus this is a possible trapezoid.
If you wan't to show that a pentagon has no right angles, then don't put any right angle signs in the figure.
ARAB IS A HORSE RIGHT?
polygon and rectangle
a square, rectangle, rhombus.....
That's exactly what the box means! That box is there to show that an angle is right, as right angles can have different properties than acute or obtuse angles.
No, it is not possible to divide a trapezium into two congruent triangles. A trapezium has only one pair of parallel sides, while a triangle has no parallel sides. Therefore, it is not geometrically feasible to divide a trapezium into two congruent triangles.