Cannot show a picture, but visualise a right angled triangle. Then imagine one of the [acute] vertices chopped off by a line parallel to the opposite side.
You will then have a trapezium with two right angles. Very crudely, it should look like the figure below:
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it is impossible i think. BUT if u want to know go on google type in a hexagon with 3 right angles then click mages and maybe it will show u.
Draw a right angle (90o). Bisect the right angle and there will be two 45o angles. Bisect one of the 45o angles and there will be one 45o angle and two 22.5o angles. A 67.5o angle includes the 45o angle and the 22.5o angle next to it, totaling 67.5o.
An equilateral triangle is a triangle where all sides are the same length and all three angles are the same. The sum of the angles of a triangle is 180 degrees. 180 ÷ 3 = 60
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the only way for a right triangle to have a line of symmetry, is if the legs of the triangle are congruent. Or you can show that both non-right angles are congruent (45 degrees). you may also prove that the altitude of the triangle bisects the hypotenuse or that it equals 1/2 of the hypotenuse.