6x-x+15-9= 6x-x=5x 15-9=6 5x+6=0 5x=-6 x=-1.2
x(x2+5x+6)
5x + 4 = 6x - 2Add 2 to each side of the equation:5x + 6 = 6xSubtract 5x from each side:6 = x
18 + 7x - 12 + 5x = ?18 - 12+ 7x - 5x = ?6 + 2x = ?
If we recall that (5 cows plus 1 cow) = 6 cows, it immediately becomes apparent that5x plus 1x = 6x.
6x-x+15-9= 6x-x=5x 15-9=6 5x+6=0 5x=-6 x=-1.2
5x-6+3x+128x-6+128x+6
x(x2+5x+6)
It simplifies to: 12 -6x
5x + 4 = 6x - 2Add 2 to each side of the equation:5x + 6 = 6xSubtract 5x from each side:6 = x
6x + 5 = 0 (I'm assuming) 6x = -5x = -5/6
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
5x^2 + 6x + 9 + (?) = -x^2 +3x + 3 (?) = -5x^2 -6x - 9 -x^2 +3x + 3 = -6x^2 -3x -6 Ans: -6x squared +3x -6
18 + 7x - 12 + 5x = ?18 - 12+ 7x - 5x = ?6 + 2x = ?
If we recall that (5 cows plus 1 cow) = 6 cows, it immediately becomes apparent that5x plus 1x = 6x.
x = 0,1
y = 5x + 6At the x-intercept, y = 0 .5x + 6 = 05x = -6x = -6/5