0
-3x + 4y = 12
Temporary value of y:
4y = 3x + 12
y = (3x + 12) / 4
Substituting y:
-3x + 4 [(3x+12) / 4] = 12
-3x + 12x + 48 = 12
-3x + 12x = 12 - 48
9x = 12 - 48
9x = -36
x = -36 / 9
x = -4
Subtituting x to get the final value of y:
-3(-4) + 4y = 12
12 + 4y = 12
4y = 12 - 12
4y = 0
y = 0
Final answer:
x = -4
y = 0
Check:
-3x + 4y = 12
-3(-4) + 4(0) = 12
12 + 0 = 12
12 = 12
Solution 2:
-3x + 4y = 12
Temporay value of x:
3x = 4y - 12
x = (4y - 12) / 3
Substituting x to get the value of y:
3[(4y - 12) / 3] + 4y = 12
12y - 36 + 4y = 12
16y = 12 + 36
16y = 48
y = 48 / 16
y = 3
Substituting y to get the value of x:
-3x + 4(3) = 12
-3x + 12 = 12
-3x = 12 - 12
x = 0
Final Answer:
x = 0
y = 3
Check:
-3(0) + 4(3) = 12
12 = 12
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