It's not always to 'solve' as it is to 'simplify' EX: 15a + 3b = 45c simplifies to 5a + b = 15c
4x = 16Divide each side of the equation by 4:x = 4
33
Let x represent the unknown number and use the known numbers to solve. Set up the equation: x + 9 = 15 (subtract 9 from each side to solve for the unknown number) x = 6
try to solve and understand umay EHEHEH
Divide each side of the equation by 10 .
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
whatever the equation is write the equation in words then solve each step in a sentence.
NO!
First, subtract 3x from each side of the equation. Then, divide each side of the equation by 7 .
You kind of need to know the problem?
(Since 5 times 20 does equal 100, the solution is correct.
There is no equation in the question, only an expression. An expression cannot be solved.
I have the feeling that you were looking to find a value for each variable in this equation. Unfortunately you can only solve for each variable in terms of the other variables in this equation.
Set up the equation and solve: x + 5 = -13 (next subtract 5 from each side of the equation to solve for x) x = -18
1). Add ' 3k ' to each side of the equation. 2). Add ' 5 ' to each side. 3). Divide each side by ' 3 ' .
2y6 is an expression not an equation. This is an equation: 2y = 6 To solve that equation you divide each side of the equation by 2: 2y/2= 6/2 y = 3