15 + 3 = 7p - 4p ie 18 = 3p so p = 6
The question contains an expression, not an equation (nor inequality). An expression cannot be solved.
3p - 8 = 13 - 4p : Add 4p to both sides 7p - 8 = 13 : Add 8 to both sides 7p = 21 : Divide both sides by 7 p = 3.
To simplify 2p + 7p, you first combine the like terms by adding the coefficients of the p variable. In this case, 2p + 7p is equal to 9p. Therefore, the simplified form of 2p + 7p is 9p.
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
3p +12= 7p 7p-3p=12 12?3=4 p=4
-31=8-6p-7p -31=8-13p ==add the -6p and the - 7p together -39=13p =======move the 8 over to the other side p=3 =======divide both sides by 13 to get p by itself
7p-2p equals = 5
To solve this group together the like terms. 7p + -p = 6p Then the answer is 6p -9.
8p+5 = 11+7p= 8p-7p = 11-5p = 6
14 + 6p = 6 + 7p 8 = p
7p + 2 = 5p + 8 7p - 5p = 8 - 2 2p = 6 p = 3
An equation where P = 1
15 + 3 = 7p - 4p ie 18 = 3p so p = 6
Equilibrium occurs where Qd = QsQd - 128 + 9p = 0Qd = 128 - 9pQs + 32 - 7p = 0Qs = 7p - 327p - 32 = 128 - 9p16p = 160p = 10
4p+9-7p+2 -3p+11 p = 11/3
7p+5q=-3, p=1 7Xp+5q=-3 7+5q=-3 5p=-10 p=-2