-6s+10 = -5s 5s-6s = -10 -s = -10 s = 10
7z + 6s + s = 7z + 7s This can then be factorised using 7 as the factor: 7z + 7s = 7(z + s)
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
5/6s + 3/4 = 11/12 10/12s + 9/12 = 11/12 10/12s = (11 - 9)/12 10/s = 2 s = 5
5s - 3 = 3s - 92s = -6s = -3
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
-6s+10 = -5s 5s-6s = -10 -s = -10 s = 10
9s+6s-12s=24... Ignore the 's' for a moment giving the sum 9+6-12=24 - This results in the answer 3 x 'something' = 24. Therefore s=8 !
7z + 6s + s = 7z + 7s This can then be factorised using 7 as the factor: 7z + 7s = 7(z + s)
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
s + 3 = 6s -s -s ------------- 3 = 5s /5 /5 s=3/5 or s=.6
-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s
9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct
(s + 6)(6s - 7)
1 - s = 6 - 6s => 5s = 5 so that s = 1
5/6s + 3/4 = 11/12 10/12s + 9/12 = 11/12 10/12s = (11 - 9)/12 10/s = 2 s = 5
13s - 2