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-99 equals 12 z - 3 6z?
-99 = 12z - 3(6)zSimplifying the expression, we have:-99 = 12z - 18z = -6zDivide by -6:z = 16.5Or, if you meant 3 6 as the number, we have:-99 = 12z - 36zSimplify:-99 = -24zDivide by -24:z = 4.125
Joe has three times as many as Tom and Tom has four times as many as Mary Altogether they have 153 How many has each Mary has Tom has Joe has?
x=3y y=4z x=12z x+y+z=z+4z+12z=153 now you have the answer
How do you solve these equations by substitution 2x-5y plus 2z equals 16 3x plus 2y-3z equals -19 4x-3y plus 4z equals 18?
If you mean: 2x-5y+2z = 16 and 3x+2y-3z = -19 and 4x-3y+4z = 18 then the solutions are found as follows:- 3(2x-5y+2z = 16) => 6x-15y+6z = 48 2(3x+2y-3z = -19) => 6x+4y-6z = -38 Adding the above: 12x-11y = 10 thus eliminating z 4(3x+2y-3z = -19) => 12x+8y-12z = -76 3(4x-3y+4z = 18) => 12x-9y+12z = 54 Adding the above: 24x-y = -22 thus eliminating z 2(12x-11y = 10) => 24x-22y = 20 1(24x-y = -22) => 24x-y = -22 Subtracting the above: -21y = 42 thus eliminating x If: -21y = 42 then y = -2 So by substitution: x = -1, y = -2 and z = 4 Check: (2*-1)-(5*-2)+(2*4) = 16 Check: (3*-1)+(2*-2)-(3*4) = -19 Check: (4*-1)-(3*-2)+(4*4) = 18
Divisibility rule for 6?
Numbers are divisible by 6 if they are even and also divisible by 3. examples are 6,12,18,24,30,36,60,54,...... examples as algebric expressions 18xy+12z+6y-a,where a is divisible by 6 i.e 6,12,18...
