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The overall stopping distance would be around 122m (400ft)
This is made up of a thinking distance of 24m (79ft) and an actual stopping distance of 98m (321ft).
The thinking distance is around 3m for every 10mph of speed and the overall stopping distance is calculated as follows:
2x20 ft at 20mph
2.5x30 ft at 30mph
3x40 ft at 40mph
3.5x50 ft at 50mph
4x60 ft at 60mph
4.5x70 at 70mph
5x80 at 80mph = 400 ft james s
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If a car traveling 40mph requires 150ft to stop find the stopping distance for a car traveling 80mph?
You can use a ratio here, say 40mph/150ft = 80mph/xft then cross multiply: 40x = 150 * 80 40x = 12000 x = 300
Total stopping distance on dry pavement at the speed of 30 mph is about?
The total stopping distance for a car travelling at 30 mph on a dry surface is about 75 feet. However, you may wish to note that in most countries, driving a car on the pavement is illegal.
How far did the car travel before stopping after traveling 21 ms with a deer in the 90 meters away?
We are not told if the car just reaches the deer, or gets to some other distance before or past the deer. If it just reaches the deer, it traveled 90 metres of course. From the information supplied it doesn't matter where the deer was.
A driver of a car traveling at 52 km per hour applies brakes and accelerates uniformly in opposite directionthe car stops in 5 seconds. how far will it travel before stopping?
0.07km
If you are traveling at 55 mph and need to come to a complete stop under perfect driving conditions appromiately how many feet will your car travel before stopping?
228ft
If a car traveling 40mph requires 150ft to stop find the stopping distance for a car traveling 80mph?
You can use a ratio here, say 40mph/150ft = 80mph/xft then cross multiply: 40x = 150 * 80 40x = 12000 x = 300
What is the stopping distance for a car traveling at 30mph?
about 22 metres
What will the stopping distance be for a -2000 N of force are applied when the car is traveling 20 ms?
To calculate the stopping distance, we need more information such as the mass of the car and the acceleration. The force alone is not sufficient to determine the stopping distance.
What will the stopping distance be for a 3000kg car if 3000 N of force are applied when the car is traveling 10 ms?
The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.
What will the stopping distance be for a 3000kg car if -3000 N of force are applied when the car is traveling 10ms?
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
What will the stopping distance be for a 3000kg car if -3 000 N of force are applied when the car is traveling 10 ms?
50m
Why is the stopping distance of a car traveling uphill is less than when it is traveling on a level road?
The stopping distance of a car traveling uphill can be less than on a level road due to gravity assisting in the deceleration process. When driving uphill, the incline can help slow down the car as it works against the forward momentum. This can lead to a shorter stopping distance compared to a level road where the car solely relies on its brakes to stop.
What will the stopping distance be for a 1000-kg car if -2000 N of force are applied when the car is traveling 10 ms?
25 m
What will the stopping distance be for a 2000 kg car if -2000 n of force are applied when the car is traveling 20 ms?
200 m
What will the stopping distance be for a 2000-kg car if -2000 N of force are applied when the car is traveling 20 ms?
200 m
What will the stopping distance be for a 1,000-kg car if -2,000 N of force are applied when the car is traveling 10 m/s?
25 m
What will the stopping distance be for a 1000 kg car if -2 000 N of force are applied when the car is traveling 10 ms?
25 m
