19
The sum of 8 and 5 is 13. There is then no number with which to calculate its product.
10: 3n = 2(n + 5); 3n = 2n + 10; (subtract 2n from each side) n = 10.
6(3n+5)
5 - the other number is 3
3 and 5
The sum of 8 and 5 is 13. There is then no number with which to calculate its product.
10: 3n = 2(n + 5); 3n = 2n + 10; (subtract 2n from each side) n = 10.
One is one and all alone and evermore shall be so...
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
To subtract the sum, first calculate the total of the numbers you want to add together. Once you have the sum, simply take the number you want to subtract from that total and perform the subtraction. For example, if the sum of 3 and 5 is 8, and you want to subtract 2 from it, you would subtract: 8 - 2 = 6.
15
The question is a bit ambiguous: "the sum of the product ... " does not seem to make sense. The first 5 digit number is 10000 the first 5 digit multiple of 6 is 10002 Their product is 100020000. I am not sure what to sum, though.
the sum of 10 and the product of 7 and a number 2+5=7 2*5=10
The question, as posted, is meaningless. Make up your mind as to whether you a re interested in product or sum.
product - 5 factor x factor = product (factor x factor) - 5 you need to state what the product were. If, for example, the factors were 2 and 3, then your answer would turn out like this: your product will be: 2x3= 6 and then substract 5 6 - 5 = 1 like this: 2x3 - 5 = 1
6(3n+5)
In a subtraction sum, such as 8 - 3 = 5, the first number is called the minuend, and the second number is the subtrahend.