There are only 10 digits: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. So the answer to the question asked is 45.
The sum of all of the integers less than 100 and greater than 0 can be found in the following way:
(99 + 1) + (98 + 2) + (97 + 3) + ... + (51 + 49) + 50 = 100 + 100 + 100 + ... + 100 + 50 = 49 X 100 + 50 = 4900 + 50 = 4850.
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There are 20.
A) If a number has two digits, then the sum of its digits is less than the value of the original two-digit number.
'17' is a prime number. The sum of the digits is 1 + 7 = 8 > 7.
12
I am 87 .