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There are only 10 digits: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. So the answer to the question asked is 45.

The sum of all of the integers less than 100 and greater than 0 can be found in the following way:

(99 + 1) + (98 + 2) + (97 + 3) + ... + (51 + 49) + 50 = 100 + 100 + 100 + ... + 100 + 50 = 49 X 100 + 50 = 4900 + 50 = 4850.

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Q: Sum of all the digits less than 100?
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