For A+ 7.22
The area of a sector of a circle is proportional to the angle at the center of the sector, with 360 degrees corresponding to the full circle. Therefore, the area of the total circle for which the problem is stated is 50 X 360/110 = about 163.6 square units. The area of a circle is also equal to pi multiplied by the square of the radius of the circle, so that the radius r of this circle equals the square root of 163.6/pi = about 7.217 units. The circumference of the circle is also twice the radius multiplied by pi = 45 units, to the justified number of significant digits (limited by "50").a+ 45.33
The circumference of a circle is NOT 360 degrees. The circumference is the distance around the curve of the circle. This has a measurement unit of length, not degrees. The angular displacement, in going completely around any point is 360 degrees and that follows from the definition of a degree.
measure of central angle/360 degrees = area of sector/area of circle 110 degrees/360 degrees = 40 unit2/ pi r2 unit2 11/36 = 40/pi r2 11 pi r2 = 40 x 36 11 pi r2 = 1,440 r2 = 1,440/11 pi r = square root of 1,440/11 pi r = 20.3 unit approximately
An arc second is a measurement of an angle, so you would need to know how far away the object is. From there, there are two ways to proceed: 1. Use a circle with the distance as the radius a. find the degree fraction (degrees/360; there are 3600 arcseconds in 1 degree) b. find the circumference of the circle and multiply by the degree fraction 2. Set up a triangle and use a trigonometric function.
A circle is 360 degrees if that's what you're asking.
You do not know how to find the centre of a circle. But can you find the centre of a equilateral triangle. If your answer is yes, then you make a concentric circle and a triangle. Let me explain. First take a random point on the circle. Now from that point draw two 60 degree angles. Then take the two points where those 60 degree angles meet the circumference. Now you have three points. Now join them. You get an equilateral triangle.Now take an angle and bisect it. Do the same with the other two angles. Are they not concurrent (meet at a same point?) Well now the place they meet is the centre of the triangle. And since the centre of the triangle and the circle is same, that is the centre.
-- Circumference of the circle = (pi) x (radius) -- length of the intercepted arc/circumference = degree measure of the central angle/360 degrees
An arc can be measured either in degree or in unit length. An arc is a portion of the circumference of the circle which is determined by the size of its corresponding central angle. We create a proportion that compares the arc to the whole circle first in degree measure and then in unit length. (measure of central angle/360 degrees) = (arc length/circumference) arc length = (measure of central angle/360 degrees)(circumference) But, maybe the angle that determines the arc in your problem is not a central angle. In such a case, find the arc measure in degree, and then write the proportion to find the arc length.
360 degrees in a circle 120 degrees = 12mm 360 degrees = 36mm Therefore the circumference of the circle is 36mm.
It will represent 1/360 of a circle's circumference of 360 degrees
one three-hundred-and-sixtieth of the circumference of a circle
It is an arc comprising half the circumference.
It is a 90 degree turn or circumference/4
May things, but the probable answer sought here is a diameter of a circle, at the circumference of the circle.
The radius is 12
Divide the arc's degree measure by 360°, then multiply by the circumference of the circle.
75.37 c=(AL)(360) devided by (angle degree)
The circumference of a circle is 360 degrees so measure out five 72 degree arcs and join them to the centre of the circle.